Example: 6 CO 2 (g) + 6 H 2 O (g) C 6 H 12 O 6 (s) + 6 O 2 (g) 3. How can either reactants or products be "favored" at equilibrium? calculate G rxn from K and perform the reverse operation. And if there are more reactants than products then the reaction favors the reactants.Why are products favored at equilibrium?Why are the products favored?When the amount of product in the reaction is greater than the amount of reactant, the reaction is product favoured while reactant favoured reactionWhat does it mean for a reaction to favor the products?To favor either the reactants or the products in equilibrium is to say the formation of either the reactants or products is favored, as indicated by the rate constants. Direct link to Amrit Madugundu's post How can we identify produ, Posted 7 years ago. Method of these balance equation calculator are almost same however, the final equation is shown with the exact value of coefficient and subscript. For our examples, assign x to the decrease in pressure of each reactant. As , EL NORTE is a melodrama divided into three acts. \[\ce{H_2O} \left( l \right) \rightleftharpoons \ce{H^+} \left( aq \right) + \ce{OH^-} \left( aq \right) \nonumber \], \[K = \left[ \ce{H^+} \right] \left[ \ce{OH^-} \right] \nonumber \]. This equilibrium constant is referred to as the ion-product constant for water, Kw. , the equilibrium condition is satisfied. spontaneous - product favored nonspontaneous - reactant favored combustion of propane spontaneous and exothermic NaOH (aq) + HCl (aq) spontaneous and exothermic H 2O (l) H 2 (g)+ O 2 non-spontaneous H 2 (g)+ O 2 H 2O (l) spontaneous and exothermic Many spontaneous reactions are exothermic. The \(Q\) equation for this example is the following: \[Q = \dfrac{[\ce{H3O^{+}(aq)}][\ce{CH3CH2CO2^{-}(aq)}]}{[\ce{CH3CH2CO2H(aq)}]} \nonumber \]. Concentrations of reactants are multiplied together on the bottom. Southwest Flights To Gatlinburg, The amount of products and reactants at equilibrium can be favored, their amounts just won't change once they reach . Step 1: Write the \(Q\) formula. The cookie is set by GDPR cookie consent to record the user consent for the cookies in the category "Functional". 3 What do we mean by an equilibrium that favors the reactants? Kf and Kr remain unequal, but the respective rate will be equal due to the change in concentration. The equilibrium constant (\(K\)) is a mathematical relationship that shows how the concentrations of the products vary with the concentration of the reactants. This means that you can have more product than reactant, or more reactant than product. Reactant-favored and Product-favored reactions. Direct link to tmabaso28's post Can i get help on how to , Posted 7 years ago. MITs Alan , In 2020, as a response to the disruption caused by COVID-19, the College Board modified the AP exams so they were shorter, administered online, covered less material, and had a different format than previous tests. In fact, iron metal will reduce Sn 2+, the reverse of the net reaction shown above. \[Q_c = \dfrac{(0)^2}{(0.04)(0.09)^3}\nonumber \]. Zbigniewa Zieliskiego do katedry koszaliskiej, Nauczanie spoeczne Kocioa zwraca uwag na ksztatowanie umysw, serc i sumie ludzi wieckich, Fatimski Kwadrans opowiedzmy dzieciom o Fatimie, Abp Jdraszewski: eby przyszo zwycistwo, trzeba o nie walczy, Nie zamiataj pod dywan, zmieniaj mentalno. If you have information about one or more reactants, select Reactant Amount Given; Otherwise, select Product Amount Given. 9 lat temu powstao Centrum Ochrony Dziecka, Papie: kobiety myl inaczej ni mczyni, lepiej ni my, W centrum zabieganego Manhattanu powstaje kaplica wieczystej adoracji, Ks. Unit 7 Quiz 2 Flashcards | Quizlet 12 What happens to the concentrations of reactants and products at equilibrium? John Sidoti Icac Outcome, _A__ 6. a. Setting up the Equation for the Equilibrium Constant Examples Video 1 . or products are favored. When K c 1, both reactant and product concentrations are significant and it is necessary to use the equilibrium constant to calculate equilibrium concentrations. d. Once started, a reactant-favored process will continue on its own. So therefore, in the state that this equation is the products are favored. To determine \(Q\), the concentrations of the reactants and products must be known. PDF Ch 14 Handouts (all) product or reactant favored calculator - sportifsengages.com How do you know if a reaction is at equilibrium? 11 Votes) Equilibrium constant (K) for any reaction is the ratio of Rate constant for Forward reaction (Kf) to the Rate constant for Backward reaction (Kr). Therefore, the side that is lower in energy is favored at equilibrium.What do we mean by an equilibrium that favors the reactants?In an equilibrium reaction, if there are more products present than reactant the reaction favors the product. After finding x, you multiply 0.05 to the 2.0 from 2.0-x and compare that value with what you found for x. This equilibrium constant is referred to as the ion-product constant for water, Kw. It possible to calculate the conversion without using internal solvents.You can remove the sample time to time take GCMC chromatogram. A product-favored process will start on its own without any initial energy input. How is the Reaction Constant (Q) affected by change in temperature, volume and pressure ? While gas changes concentration after the reaction, solids and liquids do not (the way they are consumed only affects amount of molecules in the substance). 22 What factors affect equilibrium and how? 21 Which of the following is not true about a system at equilibrium? (b) Calculate the value for ? This cookie is set by GDPR Cookie Consent plugin. HCl ( g) + NaOH ( aq) NaCl ( aq) + H 2 O ( l) with [ HCl] = 3.2 [ NaOH] = 4.3 [ NaCl] = 6 Solution Step 1: Write the Q formula. Jeeli chcesz wesprze finansowo nasz wsplnot, moesz to zrobi dokonujc przelewu na nasze konto bankowe: Bg zapa za wszystkie, nawet najdrobniejsze,ofiary na rzecz naszej parafii! product or reactant favored calculator , the equilibrium condition is satisfied.What factor does equilibrium constant depend on?Equilibrium constant depends on temperature and is independent of the actual quantities of reactants and products, the presence of a catalyst and the presence of inert material. very weak acids will be reactant favored bases will be reactantfavored-weak.- --weak stronger than #3 butstill weak strongerthan#4 but still weak where possible classify these systems as reactant favored or product favored at 298K. For example, consider the \(Q\) equation for this acid/base reaction: \[\ce{CH_3CH_2CO_2H(aq) + H_2O(l) <=> H_3O^{+}(aq) + CH_3CH_2CO_2^{-}(aq)} \nonumber \]. Najwitszej Maryi Panny Krlowej Polski > Bez kategorii > product or reactant favored calculator 11 czerwca 2022 hillsville, va labor day flea market 2021 natural disasters after 2010 By calculating Q (products/reactants), you can compare it to the K value (products/reactants AT EQUILIBRIUM) to see if the reaction is at equilibrium or not. A Measure of How Far a Reaction Goes - Chemistry LibreTexts Top. It is important to remember that even though the concentrations are constant at equilibrium, the reaction is still happening!Which of the conditions is always true at equilibrium true at equilibrium?A state in which the reactants and products have the same concentration with no change in time is represented as chemical equilibrium. If the value of K is greater than 1, the products in the reaction are favored. Chemical reactions with a positive D G have been described here as reactant-favored, meaning that, when the reaction is completed, there are more reactants that products. c) Discuss the effect of increasing temperature on the extent of the reaction. 8 Product- or Reactant-Favored Reactions and Thermodynamics Vocabulary At equilibrium the number of reactant and product molecules stay constant. Direct link to Natalie 's post in the example shown, I'm, Posted 7 years ago. You also have the option to opt-out of these cookies. Because \(Q\) < K, the reaction is not at equilibrium and proceeds to the products side to reach dynamic equilibrium once again. Functional cookies help to perform certain functionalities like sharing the content of the website on social media platforms, collect feedbacks, and other third-party features. Born and raised in the city of London, Alexander Johnson studied biology and chemistry in college and went on to earn a PhD in biochemistry. Answer: Q= 0.436 and the reaction favors the products. A strong acid or a base means that they have a lot of energy and are very reactive while weaker acids and bases have lower energy.Why do weak acids have equilibrium?Weak acids only dissociate partially in water. Which of the following is not true about a system at equilibrium? Answer: \(Q=0\), the reaction shifts right. There is no tendency to form more reactants or more products at this point. Set up a table for displaying the initial pressures, the changes in pressure, and the equilibrium pressures. Figure 5.14 The productfavored oxidation of iron. Product- or Reactant-Favored?(a) Is the combination reacti | Chegg.com What is equilibrium position in chemistry? The equilibrium constant is a ratio of the concentration of the products to the concentration of the reactants. Answer of problem . 167. In his writing, Alexander covers a wide range of topics, from cutting-edge medical research and technology to environmental science and space exploration. Explain what the value of \(K\) means in terms of relative concentrations of reactants and products. The equilibrium constant expression is a mathematical relationship that shows how the concentrations of the products vary with the concentration of the reactants. The equilibrium constant of a chemical reaction is the value of the reaction quotient when the reaction has reached equilibrium. 3. a. a) Qualitatively predict whether the reaction will be product or reactant favored. You use the 5% rule when using an ice table. \(K_{eq}\) is very large, indicating that mostly \(\ce{O2}\) is present in an equilibrium system, with very little \(\ce{O3}\). Iron. Wykonanie strony: BartoszDostatni.pl Nowoczesne Strony Parafialne, Korzystanie z niniejszej witryny oznacza zgod na wykorzystywanie plikw cookies. very weak than strong bases. Q c is equal to K c. If this is true, then the reaction is at equilibrium. 1. D. The reaction reaches equilibrium at 1.5 seconds. *Note that the only product is a solid, which is defined to have a value of 1. There are three possible scenarios to consider: In this case, the ratio of products to reactants is less than that for the system at equilibrium. 2 What side does equilibrium favor? Hence, the ratio does not contain units. Solved Using values of delta Gf, calculate delta Grxn for - Chegg Necessary cookies are absolutely essential for the website to function properly. 3) Input amount available. If the value of \(K\) is greater than 1, the products in the reaction are favored. 11 junio, 2022. Q is used to determine whether or not the reaction is at an equilibrium. Concentrations of products are multiplied on the top of the expression. Question: Using values of delta Gf, calculate delta Grxn for the following reaction. 6 What does it mean for a reaction to favor the products? In any acid-base reaction, the equilibrium will favor the reaction that moves the proton to the stronger base. Not completely on product or reactant side - have some of each "product favored" - mostly product "reactant favored" - mostly reactant 2. with \(K = 1.34\). No side is favored and no shift occurs. Examples: From the equilibrium constant K tell whether the reactants or products are favored. "Dynamic Equilibrium" forward rate = reverse rate reactions happen, but cancel each other out, so that no overall change o "steady state" 3. Jules. : 603 270 400. Free Energy and Equilibrium. powder, sprayed into a bunsen burner. product or reactant favored calculator - otisspankmore.com Products are highly dependent on the nucleophile /base used. http://www.chem.purdue.edu/gchelp/howtosolveit/Equilibrium/ICEchart.htm. Direct link to Everett Ziegenfuss's post Would adding excess react, Posted 6 years ago. Calculate the value of equilibrium constant for this reaction at 25 oC. Step 4: Compare \(Q\) to K. Because \(K=0.04\) and \(Q=0\), \(K > Q\) and the reaction will shift right to regain equilibrium. Example: . After completing his doctoral studies, he decided to start "ScienceOxygen" as a way to share his passion for science with others and to provide an accessible and engaging resource for those interested in learning about the latest scientific discoveries. The value of Q c must become smaller before the reaction can . . The system shifted to relieve the stress. \(\ce{N_2(g) + O_2(g) \rightleftharpoons 2NO(g)}\). Use equilibrium constant expressions to solve for unknown concentrations. state Removing a "reactant" from a chemical system. You need to ask yourself questions and then do problems to answer those questions. Provide the formula for each ionic compound in the table. An input table will be created. This cookie is set by GDPR Cookie Consent plugin. . K is the equilibrium constant. Reactant or Product Favored - YouTube If the Gr0 of a reaction is __________, the reaction is at equilibrium and does not favor product or reactant. . The Reaction Quotient is shared under a CC BY 4.0 license and was authored, remixed, and/or curated by Kellie Berman, Rebecca Backer, Deepak Nallur, & Deepak Nallur. Is the reaction enthalpy or entropy driven? 1) Input a reaction equation to the box. A comparison of \(Q\) with \(K\) indicates which way the reaction shifts and which side of the reaction is favored: Another important concept that is used in the calculation of the reaction quotient is called an activity. How to Study. Wittenberg is a nationally ranked liberal arts institution with a particular strength in the sciences. formula written above the arrow is used as a catalyst in the reaction (aq) reactant or product in an aqueous solution . c. Is the reaction predicted to be spontaneous at higher temperatures? Consider the reaction2H2O(g) + 2Cl2(g) ---> 4HCl(g) + O2(g)for which H = 114.4 kJ and S = 128.9 J/K at 298.15 K.(1) Calculate the entropy change of the UNIVERSE when 1.743 moles of H2O(g) react under standard conditions at 298.15 K.Suniverse = J/K(2) Is this reaction reactant or product favored under standard conditions?_____reactantproduct(3) If the reaction is product favored, is it . Using values of H f and S, calculate G rxn for the following reaction. Thus, a system in chemical equilibrium is said to be in stable state. 130. in the example shown, I'm a little confused as to how the 15M from the products was calculated. Their conjugate bases are strong. \[\ce{CO(g) + H_2O(g) \rightleftharpoons CO_2(g) + H_2(g)} \nonumber\], \[Q_c = \dfrac{[CO_2][H_2]}{[CO][H_2O]} \nonumber\]. Only the concentration of the reactants is constant. product or reactant favored calculator police academy columbia mo June 29, 2022. predcasny dochodok 1961 . Figure 5.14 The productfavored oxidation of iron. Does equilibrium favor reactants or products?The equilibrium constant expression is a mathematical relationship that shows how the concentrations of the products vary with the concentration of the reactants. No balance necessary. (B) It would become more positive because the reactant molecules would collide more often. Chemistry: The Molecular Science With General Chemistry (1st Edition) Edit edition Solutions for Chapter 18 Problem 8E: Product- or Reactant-Favored? . Any "stress" that alters one of these rates makes the system "shift" . *Note that the coefficients become exponents. Hooray! (a) Is the combination reaction of hydrogen gas and chlorine gas to give hydrogen chloride gas (at 1 bar) predicted to be product-favored or reactant-favored at 298 K? product or reactant favored calculator - brijnaari.com Can be used to predict if a reaction is product-or reactant-favored The value varies with only with temperature It is constant at a given temperature It is independent of the initial concentration The larger the value of K c (K c > 1) the more product-favored is the reaction The smaller the value of K c (K c << 1) indicates In the section "Visualizing Q," the initial values of Q depend on whether initially the reaction is all products, or all reactants. These cookies help provide information on metrics the number of visitors, bounce rate, traffic source, etc. Reaction score. As detailed in the above section, the position of equilibrium for a given reaction does not depend on the starting concentrations and so the value of the equilibrium constant is truly constant. *Note that the solids have a value of 1, and multiplying or dividing by 1 does not change the value of K. \[\ce{P_4} \left( s \right) + 6 \ce{Cl_2} \left( g \right) \rightleftharpoons 4 \ce{PCl_3} \left( s \right) \nonumber \], \[K = \dfrac{1}{\left[ \ce{Cl_2} \right]^6} \nonumber \]. A strong acid or a base means that they have a lot of energy and are very reactive while weaker acids and bases have lower energy. 2. Because the activity of a liquid is 1, we can omit the water component in the equation. 18 What happens when a chemical reaction reaches equilibrium? When chemical equilibrium is established, the concentrations of reactants and products do not change. The cookie is used to store the user consent for the cookies in the category "Other. 7 Which statement is true about a chemical reaction at equilibrium? A reversible chemical reaction is one in which the products, as soon as they are formed, react to produce the original reactants. For very small values of, If we draw out the number line with our values of. Explanation: Kc = [P.concentration]x [R.concentration]y. Direct link to Zenu Destroyer of Worlds (AK)'s post if the reaction will shif, Posted 7 years ago. Q c is larger than K c. The system contains too much product and not enough reactant to be at equilibrium. Once a chemical system has reached equilibrium: both the forward and reverse reactions continue to occur. Since the numerator would have to be greater than the denominator in this case to yeild answer greater than 1, therefore the relative product concentration would have to be greater than that of reactants. Category: science chemistry. When a reaction reaches equilibrium, then there is no net change in concentration and the reactants and products are forming at the same rate. Once a chemical system has reached equilibrium: both the forward and reverse reactions continue to occur.What factors affect equilibrium and how?The temperature, pressure, and concentration of the system are all factors that affect equilibrium. Concentration of Product C when k2 much greater than k1 in 1st Order 10 Does equilibrium favor the strong or weak acid? The ratio of products to reactants is less than that for the system at equilibriumthe concentration or the pressure of the reactants is greater than the concentration or pressure of the products. If K. A reaction reaches equilibrium position when it has no further tendency to change; that is, the reaction does remain spontaneous in neither direction . \[\ce{HCl(g) + NaOH(aq) \rightleftharpoons NaCl(aq) + H_2O(l)} \nonumber\]. b, product-favored; negative enthalpy & positive entropy (spontaneous process) 8) H rxn = -352.9 KJ/mol, Srxn = + 21.4 J/mol.K & entropy change is expected to be positive as calculated because one mole oh H 2 gas is formed in product as well as the solid Mg(OH) 2 has more atoms than any compound in the reactant side. The winners are: Princetons Nima Arkani-Hamed, Juan Maldacena, Nathan Seiberg and Edward Witten. In chemical equilibrium, the rate of the forward reaction is equal to the rate of the backward reaction. 2 CH2OH(g) + 3 O2(g) 2 CO2(g) + 4H2O(g) Species AH (kJ/mol-rxn) S (J/K mol-rxn) CH2OH(g) -210.1 239.7 O2(g) 0 205.1 CO2(g) -393.5 213.7 H2O(g) -241.8 188.8 9. Remember, the square brackets mean concentration, in molarity, if it is given in some other unit you must calculate molarity. Where possible, classify these systems as reactant-favored or product-favored at 298 K. If the direction cannot be determined from the information given, classify the reaction as "Insufficient information." when setting up an ICE chart where and how do you decide which will be -x and which will be x? How do you know if an equation favors products or reactants? Calculate A,G for the reaction below at 25 C, Is this reaction product or reactant favored? If the direction cannot be determined from the information given, classify the reaction as "insufficient information The new equilibrium has an increased amount of product. Explanation and examples of the terms Reactant Favored and Product Favored in equilibrium.LeanThink.orghttps://www.instagram.com/lean.think/ Does equilibrium favor the strong or weak acid? This expression might look awfully familiar, because, From Le Chteliers principle, we know that when a stress is applied that moves a reaction away from equilibrium, the reaction will try to adjust to get back to equilbrium. The cookie is used to store the user consent for the cookies in the category "Performance". 4) Click the 'Calculate' button. Is the reaction spontaneous at 298 K? clarification on "favoring"product or reactant - CHEMISTRY COMMUNITY Because the activity of a liquid is 1, we can omit the water component in the equation. General Steps -. Which statement is true about a chemical reaction at equilibrium? In the previous section, you learned about reactions that can reach a state of equilibrium, in which the concentration of reactants and products aren't changing. The balanced equation is as follows: {eq}Fe_2O_3 + 3CO -> 2Fe + 3CO_2 {/eq} Step 2: Calculate the amounts of reactant from the amounts of product present using stoichiometry after the equation is . It does, however, depend on the temperature of the reaction. in Chemistry. If the value of K is less than 1, the reactants in the reaction are favored.What side does equilibrium favor?Remember, it is favorable for a system to go from high energy to low energy. A reaction cannot change between being product-favored and being reactant-favored when. { Balanced_Equations_and_Equilibrium_Constants : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", Calculating_an_Equilibrium_Concentration : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", Calculating_An_Equilibrium_Concentrations : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", Calculating_an_Equilibrium_Constant_Kp_with_Partial_Pressures : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", Determining_the_Equilibrium_Constant : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", Difference_Between_K_And_Q : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", Dissociation_Constant : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "Effect_of_Pressure_on_Gas-Phase_Equilibria" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", Equilibrium_Calculations : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", Kc : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", Kp : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", Law_of_Mass_Action : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", Mass_Action_Law : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", Principles_of_Chemical_Equilibria : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", The_Equilibrium_Constant : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", The_Reaction_Quotient : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()" }, { "Acid-Base_Equilibria" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", Chemical_Equilibria : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", Dynamic_Equilibria : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", Heterogeneous_Equilibria : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", Le_Chateliers_Principle : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", Physical_Equilibria : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", Solubilty : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()" }, [ "article:topic", "Reaction Quotient", "showtoc:no", "license:ccby", "licenseversion:40", "author@Kellie Berman", "author@Rebecca Backer", "author@Deepak Nallur" ], https://chem.libretexts.org/@app/auth/3/login?returnto=https%3A%2F%2Fchem.libretexts.org%2FBookshelves%2FPhysical_and_Theoretical_Chemistry_Textbook_Maps%2FSupplemental_Modules_(Physical_and_Theoretical_Chemistry)%2FEquilibria%2FChemical_Equilibria%2FThe_Reaction_Quotient, \( \newcommand{\vecs}[1]{\overset { \scriptstyle \rightharpoonup} {\mathbf{#1}}}\) \( \newcommand{\vecd}[1]{\overset{-\!-\!\rightharpoonup}{\vphantom{a}\smash{#1}}} \)\(\newcommand{\id}{\mathrm{id}}\) \( \newcommand{\Span}{\mathrm{span}}\) \( \newcommand{\kernel}{\mathrm{null}\,}\) \( \newcommand{\range}{\mathrm{range}\,}\) \( \newcommand{\RealPart}{\mathrm{Re}}\) \( \newcommand{\ImaginaryPart}{\mathrm{Im}}\) \( \newcommand{\Argument}{\mathrm{Arg}}\) \( \newcommand{\norm}[1]{\| #1 \|}\) \( \newcommand{\inner}[2]{\langle #1, #2 \rangle}\) \( \newcommand{\Span}{\mathrm{span}}\) \(\newcommand{\id}{\mathrm{id}}\) \( \newcommand{\Span}{\mathrm{span}}\) \( \newcommand{\kernel}{\mathrm{null}\,}\) \( \newcommand{\range}{\mathrm{range}\,}\) \( \newcommand{\RealPart}{\mathrm{Re}}\) \( \newcommand{\ImaginaryPart}{\mathrm{Im}}\) \( \newcommand{\Argument}{\mathrm{Arg}}\) \( \newcommand{\norm}[1]{\| #1 \|}\) \( \newcommand{\inner}[2]{\langle #1, #2 \rangle}\) \( \newcommand{\Span}{\mathrm{span}}\)\(\newcommand{\AA}{\unicode[.8,0]{x212B}}\), status page at https://status.libretexts.org, If \(Q>K\), then the reaction favors the reactants.